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March 27, 2017

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(b+27)/(b^(2)-1) - 1/(b+1) = (b-2)/(b-1)

  • Math - ,

    multiply each term by b^2 - 1 , which is (b+1)(b-1) to get

    b+27 - 1(b-1) = (b-2)(b+1)
    b+27 - b + 1 = b^2 - b - 2
    b^2 -b -30 = 0
    (b-6)(b+5) = 0
    b = 6 or b = -5

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