Posted by Marc on Monday, July 23, 2012 at 7:51pm.
From a normal distribution table, 97.5% probability corresponds to +1.96σ.
Thus μ±1.96σ corresponds to 95% of all years.
1.96σ = 1.96*3.5=6.86"
Therefore 95% of the years have precipitation between 72±6.86"
n1-25, n2-36, s1 power 2=50, s2 2 power=72, m1=100. m2=105
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