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September 30, 2014

September 30, 2014

Posted by **Gigi** on Sunday, July 22, 2012 at 10:43pm.

1) rsecθ = 3

2) r=5/cosθ-2sinθ

3) r=5cscθ

- math -
**Reiny**, Sunday, July 22, 2012 at 11:26pmwe know r^2 = x^2 + y^2 and x/r =cosØ, y/r = sinØ

given:

rsecØ = 3

r = 3/secØ

r = 3cosØ

r = 3(x/r)

r^2 = 3x

x^2 + y^2 = 3x , rewrite it any way you want.

the last one is done the same way

2nd :

I will assume you r = 5/(cosØ-2sinØ

r = 5/(x/r - 2y/r)

r = 5/((x-2y)/r)

r = 5 * r/(x - 2y)

1 = 5/(x-2y)

x-2y = 5

- math -
**topology**, Thursday, October 4, 2012 at 3:10am5. Find the Cartesian form of the equation, r3 = 3r cosØ.

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