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9x*x+25y*y+15x*y+12x-20y+16*3x-5y-4
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could you walk-through the steps to solving this problem because I am stuck;
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Is this correct now after i revised it
Multiply. 3xy^2(5xy-4x+6y) 3xy^2(5xy)=15x^2y^3 3xy^2(-4x)=-12x^2y^2 3xy^2(6y)=18xy^3 so i
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4(x+3)=24 4(3x)=24 12x=24 12x/12= 24/12 X=2 5(x+2)=45 5x+10=45 15x=45 15x/15=45/15 x=3 5+4x=13
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3x-5(3x-7)= 2(x+9) + 45
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Add or subtract
(4x^2+15x-3)-(3x^2+5) A. 7x^2+15x-8 B. x^2+12x+2 C. x^2+15x-8 D. 7x^2+8 Please help me. Thanks
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Do you know what like terms are?
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Please Help Me !!!!!!
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@ What your looking for, I used yours and I got 3 right..
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The solution set can be described as x < -25 or x > 5.
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Related Questions
1. add or subtract
{4x^2+15x-3}-(3x^2+5) a.7x^2+15x-8** b.x^2+12x+2 c.x^2+15x-8 d.7x^2+8 2. Simplify the polynomial
1.add or subtract.
(4x²+15x-3)-(-3x²+5) A:7x²+15x-8*** B:x²+12x+2 C:x²+15x-8 D:7x²+8 2.Simplify the polynomial.
the product (2x^4y)(3x^5y^8) is equivalent to?
a.5x^9y^9 b.6x^9y^8 c.6x^9y^9 d.5x^20y^8 e.6x^20y^8
20x^2-12x+15x-9
20x^2-12x+15x-9 = 20x^2+3x-9 = (4x+3)(5x-3)
0.05x+0.25y=11
0.15x+0.05y=12 solve using the elimination method
solve using any appropriate method
0.05x+0.25y=99 0.15x+0.05y=108
solve using the elimination method
0.05x+0.25y=11 0.15x+0.05y=12
Solve by Substitution method.
15x-20y=-7 15y=4+5x
I have worked this and checked it and it does not come out true any one help me?
3x-5(3x-7)=2(x+9)+45 3x-15x-35=2x+18+45
12x+20y+15z=-60
