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April 1, 2015

April 1, 2015

Posted by **True** on Sunday, July 22, 2012 at 4:54pm.

|2 -1 1|

|1 2 6|

|3 -1 2|

___________

|2 -1 -2|

|1 2 3|

|3 -1 -1|

2X-Y+Z=-2

X+2Y+6Z=3

3X-Y+2Z=-1

A. Z

B. Y

C. X

D. NONE OF THE VARIABLES ARE REPRESENTED

- Math (Alg 2) -
**Damon**, Sunday, July 22, 2012 at 5:08pmYou replace the third column in the NUMERATOR determinant with the right hand side, NOT THE DENOMINATOR to get the third variable, Z. Therefore you got 1/Z

- Math (Alg 2) -
**Damon**, Sunday, July 22, 2012 at 5:10pmHere is a link to Cramer's rule:

http://www.purplemath.com/modules/cramers.htm

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