Posted by **Fareeha** on Sunday, July 22, 2012 at 3:48am.

when an object is 100m above the surface of earth. The earth's attraction for it is 10N. In order then the earth's attraction on the same object is only 5N. how far should be taken to object be away from surface of earth.

- physics -
**Elena**, Sunday, July 22, 2012 at 4:06am
F1 =G•m•M/R1²

F2= G•m•M/R2²

F1=10 N, F2 = 5 N

F1=2F2

G•m•M/R1² =2 G•m•M/R2²

1/R1²=2/R2²

R2=√2•R1

Earth’s radius is R = 6.378•10^6 m.

h1=100 m, h2=?

R1=R+h1

R2=R+h2

R+h2=√2• (R+h1),

h2 =[√2• (R+h1)] – R.

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