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April 17, 2014

April 17, 2014

Posted by **fa 2** on Saturday, July 21, 2012 at 7:26am.

- Physica -
**Elena**, Saturday, July 21, 2012 at 10:03amThe object has to be placed between the lens and the focus.

di= distance between the image and the lens;

do=distance between the object and the lens;

F =focal length.

do/di=h/H=1/3 =>

3•do=di

1/F =1/do-1/di,

1/F= =

=2/3•do,

do=2F/3 =2•0.15/3=0.1 m.

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