Posted by **zianna** on Saturday, July 21, 2012 at 6:53am.

a projectile is thrown with the speed of 25 meter per seconds in a direction 30° above the horizontal.

-how high does it go.

-how long does it take to reach the maximum height.

-how long does it reach the Projectile along in the air.

-how far does it go.

- physics -
**drwls**, Saturday, July 21, 2012 at 8:15am
Initial vertical velocity component =

Vy,0 = Vo sin 30 = 12.5 m/s

Maximum height is reached when

Vy,o = 12.5 m/s = g*T

T = 1.276 s

Maximum height reached = (Vy,0/2)*T = 6.25*1.276 = 7.97 m

Range = Vo*cos30*(2*T) = 55.3 m

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