Posted by **fatma** on Saturday, July 21, 2012 at 3:49am.

If a student desires to produce three times larger and an erect image from a double convex lens with focal length of 15 cm ,then he should place the object from the lens at ;

- Physica -
**Elena**, Saturday, July 21, 2012 at 9:58am
The object has to be placed between the lens and the focus.

di= distance between the image and the lens;

do=distance between the object and the lens;

F =focal length.

do/di=h/H=1/3 =>

3•do=di

1/F =1/do-1/di,

1/F= =

=2/3•do,

do=2F/3 =2•0.15/3=0.1 m.

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