Homework Help: Chemistry

Posted by Jackie on Friday, July 20, 2012 at 4:38pm.

A voltaic cell consists of Ag/Ag+2 electrode E= 0.80 and a Fe+2/Fe+3 electrode E=0.77 with the following initial molar concentrations: [Fe+2}= 0.30 M [Fe+3]= 0.10 M [Ag+]=0.30 M. What is the equilibrium concentration of Fe+3? (Assume the anode and the cathode solutions are of equal volume, and at the temperature 25 degreees Celcius)

Chemistry - DrBob222, Friday, July 20, 2012 at 10:07pm
Did you intend Ag/Ag^+ or Ag/Ag^2+. I will assume you intended Ag/Ag^+
Ag^+ + e ==> Ag Eo = 0.80
Fe^2+ ==> Fe^3+ Eo = -0.77
==================
Ag^+ + Fe^2+ ==> Ag + Fe^3+ Eocell = 0.03

Then Ecell = EoCell - (0.0592/n)log Q
where Q = (Fe^3+)/(Fe^2+)

Answer this Question

Related Questions

Chemistry - Im having trouble on a question Im not sure what it is they are ...
chemistry - Calculate [Fe^2]+ when the cell reaction reaches equilibrium? A ...
chemistry - A voltaic cell is constructed based on the following reaction and ...
Chemistry - Calculate [Fe^2]+ when the cell reaction reaches equilibrium? A ...
Chem -plz check work - so i've worked on this some more, now I am asking if ...
chemistry 2 - A voltaic cell is constructed with an Ag/Ag+ half-cell and a Pb/...
Chemistry - One half-cell of a concentration cell consists of a silver wire ...
Chemistry - Little confusing!! I need help PLZ!!! Two half cells in a galvanic ...
College Chemistry - A Galvanic cell consists of Mg electrode in a 1.0 mol L -1 ...
Chem (electronegativity) - Calculate the E°cell for the following voltaic ...

For Further Reading

First Name:
School Subject:
Answer: