Tuesday

July 29, 2014

July 29, 2014

Posted by **Bernard** on Friday, July 20, 2012 at 12:03pm.

derivative

also,

f(x)= (3x+x^4)^(3/2)/(7x^2-1)

- Calc -
**Reiny**, Friday, July 20, 2012 at 12:28pmfor the first one, since 2+e^2 is a constant, you simply get

f'(x) = (2+e^2)(2x + 1/x)

(are you sure there was no typo ?)

for the 2nd use the quotient rule, give it a try, let me know what you got

- Calc -
**Bernard**, Friday, July 20, 2012 at 12:30pmthe first one should be (x^2+lnx)(2+e^x) sorry

- Calc -
**Reiny**, Friday, July 20, 2012 at 4:24pmf(x) = (x^2+lnx)(2+e^x)

f'(x) = (x^2 + lnx)(e^x) + (2+e^x)(2x + 1/x)

I used the product rule,

expand and simplify if needed

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