Posted by Bernard on Friday, July 20, 2012 at 12:03pm.
- Calc - Reiny, Friday, July 20, 2012 at 12:28pm
for the first one, since 2+e^2 is a constant, you simply get
f'(x) = (2+e^2)(2x + 1/x)
(are you sure there was no typo ?)
for the 2nd use the quotient rule, give it a try, let me know what you got
- Calc - Bernard, Friday, July 20, 2012 at 12:30pm
the first one should be (x^2+lnx)(2+e^x) sorry
- Calc - Reiny, Friday, July 20, 2012 at 4:24pm
f(x) = (x^2+lnx)(2+e^x)
f'(x) = (x^2 + lnx)(e^x) + (2+e^x)(2x + 1/x)
I used the product rule,
expand and simplify if needed
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