Posted by **Bruce** on Friday, July 20, 2012 at 10:32am.

A uniform brass disk of radius R and mass M with a moment of inertia I about its cylindrical axis of symmetry is at a temperature T = 45 °C. Determine the fractional change in its moment of inertia if it is heated to a temperature of 125 °C. (The linear expansion coefficient for brass is 1.90 10-5 °C−1.)

I tried finding the change in volume and using that ratio, but it isn't correct. Im not sure what the best approach is. Thank you for any suggestions!

- physics -
**ajayb**, Friday, July 20, 2012 at 12:02pm
You have been given the linear expansion coefficient - find increase in radius R and then find the disk's MI.

- physics -
**Elena**, Friday, July 20, 2012 at 2:37pm
ΔR=R•α•ΔT=R•1.9•10^-5•(125-45)=0.00152•R

R1=R+0.00152•R =R•1.001525

I=mR²/2

I1= mR1²/2= mR²•1.001525²/2=1.003• mR²/2=1.003•I

I1/I=1.003 or

I/I1=1/1.003=0.997

- physics -
**Bruce**, Monday, July 23, 2012 at 11:09pm
thank you!

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