Math
posted by Marshall on .
A student is in a 20 week calc class. The function f(t)=5050e^0.2t f(t) measures the students problem speed in t weeks
how many problems per hour can a student solve at the beginning of the course
 how many problems per hour can a student solve halfway through the course
at what rate is the students problem speed increasing 6 weeks into the course

at the beginning  > t = 0
f(0) = 50  50e^0 = 0
halfway through course  > t=10
f(10) = 50  50e^2 = 319
your equation makes no sense
Your function is a decreasing function.
Why would the student's speed decrease as the course progresses ?
Check for typo. 
how to figure out rate