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March 30, 2017

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A student is in a 20 week calc class. The function f(t)=50-50e^0.2t f(t) measures the students problem speed in t weeks

-how many problems per hour can a student solve at the beginning of the course

- how many problems per hour can a student solve halfway through the course

-at what rate is the students problem speed increasing 6 weeks into the course

  • Math - ,

    at the beginning --- > t = 0
    f(0) = 50 - 50e^0 = 0

    half-way through course --- > t=10
    f(10) = 50 - 50e^2 = -319

    your equation makes no sense
    Your function is a decreasing function.
    Why would the student's speed decrease as the course progresses ?

    Check for typo.

  • calc - ,

    how to figure out rate

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