Posted by Jake on Thursday, July 19, 2012 at 9:39pm.
The reflected sound has a higher frequency, so the insect is approaching.
(delta f)/f = 0.4/40 = 0.01 = 2 V/a
The number 2 accounts for Doppler shift incident and reflected sound
a is the sound speed. Assume a = 340 m/s
V = 1.7 m/s
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