Posted by lanre on Thursday, July 19, 2012 at 9:30pm.
The equation of the wave is
y(x,t)= A•sin(2πx/λ - 2πt/T).
Given equation is
y(x, t) = (0.0210 m)sin[(6.91 m^−1)x + (2.38 s^−1)t
Therefore,
A = 0.0210 m
2π/λ =6.91
λ=2π/6.91=0.909 m
2πt/T= 2.38
T=2πt/ 2.38=2.64 s
λ=vT
v= λ/T=(2π/6.91)/( 2πt/ 2.38)=
=2.38/6.91=0.344 m/s
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