Posted by Adam on Thursday, July 19, 2012 at 9:17pm.
distance=velocity*time
2*canyonwidth=speedsound*time
solve for canyon widthhttp://www.ausetute.com.au/calcelemf.html
2cw=340*3/2=510m but the answer given is 514.5m?
Sound waves move through air at sea level at a velocity of 343 m/s at 20ºC.
x=343•3/2=514.5 m
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