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physics

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The tension in a 2.8-m-long, 1.2-cm-diameter steel cable (ρ = 7800 kg/m3) is 825 N. What is the fundamental frequency of vibration of the cable?

  • physics - ,

    Fundamental wavelength = 5.6 m
    V = Wave speed = sqrt(T/(ñ*A))
    T = tension = 825 N
    A = pi*d^2/4 = cross sectional area of cable
    d = 0.012 m
    Solve for V. Then use
    Fundamental frequency
    = V/(Fund. Wavelength)

  • physics - ,

    thanks! but whats ñ

  • physics - ,

    That was supposed to be your density symbol, rho. I never know what Greekm (or Spanish) symbols are going to pop up when I cut and paste.

  • physics - ,

    thanks! may I ask how you calculate the fundamental wavelength or is it a constant?

  • physics - ,

    calculated**

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