Posted by Jemima on Thursday, July 19, 2012 at 6:21pm.
I don't see an "exponential model below" .
N(t)= 600/1+24e^-0.21t
I am sure you meant
n(t) = 600/(1 + 24e^-.21t )
a) let t=0, N(0) = 600/(1+24e^0) = 600/25 = 24
b) As t gets larger e^-.21t gets smaller
e.g. if t = 20, e^-4.2 = .015
so 24e^-.21t gets smaller
and our formula approaches 600/(1+0) = 600
so the maximum would be 600
c) sub in t=14
N(14) = 600/(1+24e^-2.94) = appr 264
d) N'(t) = -600(1+24e^-.21t)^-2 * 24(-.21)e^-.21t
sub in t=14
you do the button-pushing (I got 31)
Thanks!
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