Posted by James on Wednesday, July 18, 2012 at 11:49pm.
(a) Kepler's Third law for objects orbiting the sun says:
a^3 = P^2, where P is the period in years and a is the semimajor axis in a.u. .
Since P = 72.0 y,
a = 17.31 a.u.
(b) 2a = (perihelion distance)+ (aphelion distance)
Therefore
aphelion (greatest) distance = 34.0 a.u.
The perihelion distance is
0.6 au = (1 - e) a , so
1 - e = 0.6/17.3 = 0.0347
e = 0.9653
=
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