so would my answer be 15ml
How much 0.300 M NaOH is required to completely neutralize 30.0 ml of 0.15 M HClO4
Clue: M1V1=M2V2
Yes. BTW, you don't need to post a new question every time; only if it is a new one. For old ones you can answer at that post.
Thanks
To find out how much 0.300 M NaOH is required to completely neutralize 30.0 ml of 0.15 M HClO4, you can use the formula M1V1 = M2V2, also known as the dilution formula.
First, identify the values given in the problem:
M1 (initial molarity) = 0.15 M HClO4
V1 (initial volume) = 30.0 ml
M2 (final molarity) = 0.300 M NaOH
V2 (final volume) = unknown (what we're trying to find)
Now, substitute the values into the dilution formula:
(0.15 M)(30.0 ml) = (0.300 M)(V2)
Solve for V2:
(0.15)(30.0) = 0.300V2
4.5 = 0.300V2
Divide both sides by 0.300:
V2 = 4.5 / 0.300
V2 = 15 ml
Therefore, you are correct. The answer is 15 ml.