Posted by chchch on .
Given the linear equation 5y = -3x + 19, find
(a) the slope of a line perpendicular to the given line.
(b) the slope of a line parallel to the given line.
A. (a) -5/3 (b) 3/5
B. (a) -3/5 (b) 5/3
C. (a) 5/3 (b)-3/5
D. (a) 3/5 (b)-5/3
Rewrite the equation as:
y=(-3/5)x + 19/5
which makes the slope as (-3/5)
Lines that are parallel have the same slope.
Two lines that are perpendicular to each other have the product of the slope equal to -1.
That should be enough for you to make the right choice.