Posted by Jean on Wednesday, July 18, 2012 at 6:05pm.
f(x) is increasing when f'(x)>0
ln(f)=-x^2/2 * e^(-x^2/2)
take the derivative.
f'/f(x)=-e^(-x^2/2)( -x)=xe^ ( )
then f'=xe^ ( ) * e^( )= xe^(-x^2)
check that.
so when x>0, f(x) is increasing.
never mind
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