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September 30, 2014

September 30, 2014

Posted by **Jean** on Wednesday, July 18, 2012 at 6:05pm.

- Business Calculus -
**bobpursley**, Wednesday, July 18, 2012 at 6:25pmf(x) is increasing when f'(x)>0

ln(f)=-x^2/2 * e^(-x^2/2)

take the derivative.

f'/f(x)=-e^(-x^2/2)( -x)=xe^ ( )

then f'=xe^ ( ) * e^( )= xe^(-x^2)

check that.

so when x>0, f(x) is increasing.

- Business Calculus -
**Justin**, Wednesday, July 25, 2012 at 3:56amnever mind

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