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April 20, 2014

April 20, 2014

Posted by **jessica hernandez** on Wednesday, July 18, 2012 at 1:05pm.

- algebra -
**Steve**, Wednesday, July 18, 2012 at 2:29pmdunno, but the roots are 2 and 13i

I assume the root given was one of the complex ones, because that would guarantee that its conjugate was also a root.

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