Tuesday
March 28, 2017

Post a New Question

Posted by on .

A vertically hanging spring has a mass of 50 N hanging from it. Under these conditions, the spring stretches 10 cm. The spring is then placed on a horizontal table and stretched 20 cm. What force is required in the second scenario?

  • physics - ,

    k•x1=m•g
    k=m•g/x1=50/0.1=500 N/m
    F= k•x2=500•0.2=100 N.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question