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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Tuesday, July 17, 2012 at 9:09pm.

- practical math -
**Jai**, Tuesday, July 17, 2012 at 9:18pmassuming the gas is ideal, we can use the Charles' Law:

V1 / T1 = V2 / T2

where

V1 = initial volume of gas

T1 = initial temp of gas

V2 = final volume of gas

T2 = final temp of gas

substituting the values to the equation,

0.20 / 333 = V2 / 533

V2 = 0.20*533/333

V2 = 0.32 cubic meter

hope this helps~ :)

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