Posted by Mercedes on Tuesday, July 17, 2012 at 8:01pm.
At only 4% of the speed of light, you can neglect relativity effects and assume the electron kinetic energy starts out as
(1/2)mV^2 = (1/1250)m c^2
where I used V = c/25.
m is the electron mass.
To stop the electron in a distance X = 0.05 m,
E*X = (1/1250)mc^2
Solve for E, the required field strength.
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