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posted by ted on Tuesday, July 17, 2012 at 6:30pm.

how to solve log basex 8=-1/2 pls help

http://www.jiskha.com/display.cgi?id=1342557692

log basex8= -1/2 so rearrange it, therefore x^-1/2 = 8 1/root(x) = 8 8root(x)=1 root(x)=1/8 x = (1/8)^2 so ur answer for x is x= 1/64

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