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August 1, 2014

August 1, 2014

Posted by **Alice** on Tuesday, July 17, 2012 at 3:51pm.

f(x) = e−3x + 5e4x

- Calc -
**Jai**, Tuesday, July 17, 2012 at 3:57pmf(x) = e^(−3x) + 5e^(4x)

Note that the derivative of e^x is equal to e^x times the derivative of the exponent with variable x:

d/dx (e^x) = e^x dx

applying this,

f'(x) = -3e^(-3x) + 20e^(4x) : First derivative

f''(x) = 9e^(-3x) + 80e^(4x) : Second derivative

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