Posted by Alice on Tuesday, July 17, 2012 at 3:51pm.
f(x) = e^(−3x) + 5e^(4x)
Note that the derivative of e^x is equal to e^x times the derivative of the exponent with variable x:
d/dx (e^x) = e^x dx
applying this,
f'(x) = -3e^(-3x) + 20e^(4x) : First derivative
f''(x) = 9e^(-3x) + 80e^(4x) : Second derivative
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