Posted by **tempest** on Tuesday, July 17, 2012 at 1:51pm.

Find four consecutive odd integers so that five times the sum of the first and third integers excceeds four times the sum of the second and last integers by 14.

- algebra -
**Steve**, Tuesday, July 17, 2012 at 2:43pm
let the integers be n-3, n-1, n+1, n+3

5(n-3 + n+1) = 4(n-1 + n+3)+14

5(2n-2) = 4(2n+2)+14

10n-10 = 8n+22

2n = 32

n=16

The numbers are 13,15,17,19

Check:

5(13+17) = 150

4(15+19)+14 = 150

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