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July 22, 2014

July 22, 2014

Posted by **Tifini** on Sunday, July 15, 2012 at 11:00pm.

- Integrated Math 1 -
**Reiny**, Sunday, July 15, 2012 at 11:08pmIn this case it is just as easy to simply expand it

= (3x)^3 + 3(3x)^2 y + 3(3x)(y^2) + y^3

so we want the second last term which is

9xy^2

- Integrated Math 1 -
**Reiny**, Monday, July 16, 2012 at 8:36amIn this case it is just as easy to simply expand it

= (3x)^3 + 3(3x)^2 y + 3(3x)(y^2) + y^3

so we want the second last term which is

9xy^2

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