Posted by **Tifini** on Sunday, July 15, 2012 at 9:18pm.

Consider y=x^2+8x+16.

What is the correct way to factor this equation?

How does this equation shift the graph of y=x^2?

A. the correct factored form is y=(x+4)^2. this shifts the graph of y=x^2 up 4 units.

B. the correct factored form is y=(x+4)^2. this shifts the graph of y=x^2 right 4 units.

C. the correct factored form is y=(x+4)^2. this shifts the graph of y=x^2 left 4 units.

D. the correct factored form is y=(x+16)^2. this shifts the graph of y=x^2 up 16 units.

E. the correct factored form is y=(x-4)(x+4). this shifts the graph of y=x^2 right 4 units and up 4 units.

- Integrated Math 1 -
**MathMate**, Sunday, July 15, 2012 at 9:31pm
The standard graph is y=x^2.

The shifted graph is

y=a(x-h)^2+k

which shifts the graph h units to the right, and k units up with a vertical multiplication factor a.

In the given problem,

h=-4,

k=0,

a=1.

Try to interpret the results.

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