In rectangle ABED, AC = 7 cm and DE = 10 cm. What is the length of AD? If necessary, round your answer to the nearest tenth.
Where is C in rectangle ABED?
the center. its a rectangle broken into the triangles
CE must be 7 also, as C bisects AE.You have a right triangle AED, so AE=14 (hypotenuse), side DE 10.
AD=sqrt(14^2-10^2)
ty5h7l,
To find the length of AD in rectangle ABED, we can use the Pythagorean Theorem.
The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In rectangle ABED, AC and DE are two sides of a right triangle with AD as the hypotenuse.
Let's label the length of AD as x.
According to the Pythagorean Theorem, we have the equation:
AC^2 + DE^2 = AD^2
Substituting the given values, we have:
7^2 + 10^2 = x^2
49 + 100 = x^2
149 = x^2
To find x, we take the square root of both sides:
√149 = √x^2
The length of AD is approximately 12.2 cm (rounded to the nearest tenth).