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August 30, 2014

August 30, 2014

Posted by **Tifini** on Sunday, July 15, 2012 at 6:47pm.

- Integrated Math 1 -
**bobpursley**, Sunday, July 15, 2012 at 6:51pmWhere is C in rectangle ABED?

- Integrated Math 1 -
**Tifini**, Sunday, July 15, 2012 at 6:52pmthe center. its a rectangle broken into the triangles

- Integrated Math 1 -
**bobpursley**, Sunday, July 15, 2012 at 7:20pmCE must be 7 also, as C bisects AE.You have a right triangle AED, so AE=14 (hypotenuse), side DE 10.

AD=sqrt(14^2-10^2)

- Integrated Math 1 -
**Anonymous**, Friday, May 31, 2013 at 2:33amty5h7l,

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