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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Sunday, July 15, 2012 at 6:03pm.

Many of my classmates have an expected return of 17.6% and a standard deviation of 34.8. Then they have the formula Prob(d>(200-17.6)/34.8 = prob. d>2.37

1-d>2.37=1-.991 = .009 chance of doubling.

I just need this problem explained to me. I'm not sure where all the numbers and information are coming from. Any help would be greatly appreciated.

- Statistics teacher needed -
**Damon**, Sunday, July 15, 2012 at 6:08pmnormal distribution problem

I do not know where your mean (expected return) and sigma are coming from. I assume some text book.

- Finance -
**Damon**, Sunday, July 15, 2012 at 6:24pmNow if we assume a mean return of 17.6%

and a sigma of 34.8%

doubling is 100% which is 82.4% above mean and tripling is 200% which is 182.4% above mean

how many sigmas is 82.4?

82.4/34.8 =2.37 sigmas to double

how many sigmas is 182.4?

182.4/34.8 = 5.24 sigmas to triple

(note you used 200 where you should have used 100 in interpreting classmate results)

- Finance -
**Damon**, Sunday, July 15, 2012 at 6:31pmNow go to tables for normal distribution:

to be 2.37 sigmas above mean:

well I only have a rough table here. For z = 2.3, F(z) = .989

for z = 2.4, F(z) = .992

so about 99% is below 2.37 sigma above mean and we only have about a 100-99 or a 1 percent chance of doubling. (you probably have more accurate tables). You will need a very accurate table though to find any probability of exceeding 5.24 sigmas above mean

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