Posted by Anonymous on .
Two astronauts, each having a mass of 89.0 kg, are connected by a 10.0 m rope of negligible mass. They are isolated in space, moving in circles around the point halfway between them at a speed of 5.60 m/s. Treating the astronauts as particles, calculate each of the following.

You orgot the rest of the question 
Damon,
anyway,
Ac = v^2/r
r = 5 m
so
Ac = 5.6^2/5 = 6.27 m/s^2
F = m Ac = 89 * 6.27 = 558 Newtons tension in line