Posted by Jack Hill on Sunday, July 15, 2012 at 4:21pm.
p=mv=40•12 =480 kg•m/s.
F=100 N,
Δt=3 s.
Impulse = F•Δt=100•3=300 kg•m/s.
p is directed to the East
F•Δt=p1 is directed to the northeast.
p and p1 make the angle α=45º
Another angle in the parallelogram of momenta is [360-(2•45)]/2=135º
Use cosine law
p(net) =sqrt(p²+p1²-2p•p1•cos α) =
=sqrt(480²+ 300² -2•480•300•cos 135º)=
=sqrt(480²+ 300² +2•480•300•0.707)= 723.9 kg•m/s.
v=p(net)/m =723.9/40=18.1 m/s
Related Questions
Physics - A 4.0 x 101 kg wind sled is gliding East across a frozen lake at a ...
physics - A wind sled has a mass of 45kg and is gliding at a speed of 2m/s over ...
Physics - A sled of mass 5.98 kg is coasting along on a frictionless ice-...
Physics - A sled of mass 5.98 kg is coasting along on a frictionless ice-covered...
Physics - An iceboat is at rest on a frictionless frozen lake when a sudden wind...
Physics - A horse draws a sled horizontally across a snow-covered field. The ...
Physics - A horse draws a sled horizontally across a snow-covered field. The ...
Physics - A horse draws a sled horizontally across a snow-covered field. The ...
Physics/Math - An iceboat is at rest on a frictionless frozen lake when a sudden...
Physics - On a frozen pond, a person kicks a 10.0 kg sled, giving it an initial ...
For Further Reading
