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precal

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sin t/(1-cos t)- 1 + cos t /sin t = 0

  • precal - ,

    Maybe you mean:

    sin t (1+cos t)/[1-cos^2 t) - (1 + cos t)/sin t = 0

    (1+cos t)/sin t - (1 + cos t)/sin t
    which is indeed zero

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