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November 27, 2014

November 27, 2014

Posted by **denise** on Sunday, July 15, 2012 at 2:51pm.

- precal -
**Damon**, Sunday, July 15, 2012 at 3:26pmMaybe you mean:

sin t (1+cos t)/[1-cos^2 t) - (1 + cos t)/sin t = 0

(1+cos t)/sin t - (1 + cos t)/sin t

which is indeed zero

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