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September 1, 2014

September 1, 2014

Posted by **candice** on Sunday, July 15, 2012 at 1:35am.

Thanks in advance :)

- math -
**Steve**, Sunday, July 15, 2012 at 1:05pmAt the maximum height of 4.9m, the ball has risen for 1 sec. (That's the amount of time it takes to fall from 1m height to 0.)

So, v = 9.8-9.8t

h = -4.9t^2 + 9.8t since h(0) = 0

at t=1.857 sec, h = 1.3, x=52 m

So, the fielder must run 65-52 = 13m in 1.857sec, or 7m/s

(assuming he doesn't extend his arm too far to grab the ball!)

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