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posted by nik Saturday, July 14, 2012 at 2:22pm.

write the equation of the hyperbola in standard form: x^2-4x-y^2+6y=9

(x-2)^2 -(y-3)^2 = 9 +4 -9 = 4 [(x-2)/2]^2 - [(y-3)/2]^2 = 1

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