Posted by GiGi on Saturday, July 14, 2012 at 12:56pm.
Hello can u help? I need a solution to calculus problem I have $500.00 to spend on fencing for a garden. The fence for the street side costs $30.00 per foot and the other three sides cost $10.00 per foot. what dimensions will give you a rectangle for the largest possible area?
How do you know it is for max area?

calculus?  Steve, Saturday, July 14, 2012 at 2:45pm
with street side length x, and yard width y, then the cost is
c = 30x + 10(x+2y)
c=500, so
500 = 40x + 20y, so
y = 25  2x
the area is given by
a = xy = x(252x) = 25x  2x^2
da/dx = 254x
da/dx=0 when x = 6.25. So, the yard is
6.25 x 12.5
The area has a max or min where da/dx = 0. Since a(x) is a parabola opening downward, it is a max.
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