Homework Help: Math

Posted by Candice on Saturday, July 14, 2012 at 4:38am.

Hi, could you please help with this question :)

Find the speed and direction of a particle which, when projected from a point 15 m above the horizontal ground, just clears the top of a wall 26.25 m high and 30 m away.

Thanks in advance

Math - Henry, Monday, July 16, 2012 at 4:33pm
h1 = 15 m.
h2 = 26.25 - 15 = 11.25 m. = Ver. dist.
from firing point to top of wall.

Y = h2 = 11.25 m.
X = 30 m.
tanA = Y/X = 11.25 / 30 = 0.375
A = 20.6 Deg. = Direction of particle.

Range = Vo^2*sin(2A)/g = 30 m.
Vo^2*sin(41.2) / 9.8 = 30
Divide both sides by sin(41.2):
Vo^2 / 9.8 = 45.5
Vo^2 = 446.3
Vo = 21.1 m/s @ 20.6 Deg. = Velocity
and direction.

Answer this Question

Related Questions

physics - An alpha particle collides with an oxygen nucleus, initially at rest. ...
physics - An alpha particle collides with an oxygen nucleus, initially at rest. ...
physics - Particle 1 is moving on the x-axis with an acceleration of 5.55 m/s2 ...
math - could you please help with this question :) Find the speed and direction ...
Physics - At a certain time a particle had a speed of 60 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 60 m/s in the positive x ...
physics - At a certain time a particle had a speed of 91 m/s in the positive x ...
physics - Particle 1 is moving on the x-axis with an acceleration of 5.55 m/s2 ...
Physics - At a certain time a particle had a speed of 16 m/s in the positive x ...
Physics - At a certain time a particle had a speed of 16 m/s in the positive x ...

For Further Reading

First Name:
School Subject:
Answer: