Posted by CombatVetUSMC on Saturday, July 14, 2012 at 1:03am.
x1=4.03 cm, x2=7.01 cm.
The left point is A, the right point is B.
Potential due to the point charge is
φ = k•q/r.
Then, at the point A
φ(A2) = -k•q2/x1,
φ(A1)+ φ(A2)=0 =>
At the point B
φ(B2) = -k•q2/x2,
φ(B1)+ φ(B2)=0 =>
Equate the right sides of the equations (1) and(2)
(d-x1)/x1 = (d+x2)/x2
=24.03•7.01/(7.01-4.03) =18.96 cm.
q1/q2 =(d-x1)/x1 =
=(18.96-4.03)/4.03 = 3.7
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