x1=4.03 cm, x2=7.01 cm.
The left point is A, the right point is B.
Potential due to the point charge is
φ = k•q/r.
Then, at the point A
φ(A2) = -k•q2/x1,
φ(A1)+ φ(A2)=0 =>
At the point B
φ(B2) = -k•q2/x2,
φ(B1)+ φ(B2)=0 =>
Equate the right sides of the equations (1) and(2)
(d-x1)/x1 = (d+x2)/x2
=24.03•7.01/(7.01-4.03) =18.96 cm.
q1/q2 =(d-x1)/x1 =
=(18.96-4.03)/4.03 = 3.7
Physic - A point charge q1=-8 is located at the orgin of a rectangular ...
physics - Find the electric potential energy for the following array of charges...
AP Physics B - Two point charges Q1 and Q2, are located a distance .20 meter ...
physics - Three point charges are arranged along the x-axis. Charge q1 = +2.75 µ...
physics - A charge of +24.3 µC is located at (4.40 m, 6.02 m) , and a charge of...
physics - A charge of +q is located at the origin, while an identical charge is ...
Physics - 2. Charge q1 is located at (0,+30 cm). Charge q2 is located at (0, -30...
Physics - The drawing shows a positive point charge +q1, a second point charge ...
Physics - Two spheres of charge q1 and q2 that are equal in magnitude (i.e. |q1...
physics - Three point charges lie in a straight line along the y-axis. A charge ...