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July 28, 2014

July 28, 2014

Posted by **Anonymous** on Friday, July 13, 2012 at 10:00pm.

5csc^2theta-3cot^2theta=2csc^2theta+3

- trig -
**Reiny**, Friday, July 13, 2012 at 11:30pm5 csc^2 Ø - 3cot^2 Ø = 2csc^2 Ø + 3

LS = 5/sin^2 Ø - 3cos^2 Ø/sin^2 Ø

= (5 - 3cos^2 Ø)/sin^2 Ø

= (5 - 3(1 - sin^2 Ø) )/sin^2 Ø

= ( 2 + 3sin^2 Ø)/sin^2 Ø

= 2/sin^2 Ø + 3sin^2 Ø/sin^2 Ø

= 2csc^2 Ø + 3

= RS

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