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April 18, 2014

April 18, 2014

Posted by **Vladimir** on Friday, July 13, 2012 at 10:53am.

The answer is supposed to be -0.613m/s^2. I'm stumped on how to get this answer. I figured out that the total distance downward the beach goes at 12 m to be 1.5 m. However, I'm not sure if that's useful or not. Any help is appreciated.

- Physics -
**Count Iblis**, Friday, July 13, 2012 at 11:43amThe speed of a shallow wave is

v = sqrt(g h) where h is the water depth. The acceleration is thus:

a = dv/dt = 1/2 sqrt(g/h) dh/dt =

1/2 sqrt(g/h) dh/dt =

1/2 sqrt(g/h) dh/dx dx/dt =

1/2 sqrt(g/h) dh/dx v =

g/2 dh/dx =

9.81/2 m/s^2 (-0.2 m/1.6 m) =

-0.613 m/s^2

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