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April 20, 2014

April 20, 2014

Posted by **James** on Friday, July 13, 2012 at 10:39am.

I know the answer is 0.09sin(0.33pi(x) - 96.00pi(t)), but how do you get the coefficient 0.33 for the x-direction? I'm aware of how to get the rest of it.

From what I understand of my text book's explanation, I've tried using (2pi)/wavelength; however, this gives me roughly 1.05.

- Physics -
**James**, Friday, July 13, 2012 at 10:39amAny help is appreciated.

- Physics -
**Elena**, Friday, July 13, 2012 at 11:55amAccording to the equation of the wave

the displacement of the particle

ξ(t)=A•sin(2 π•x/λ -2•π•f•t ) =

=0.09•sin((2 π/6)•x -2•π•48•t )=

=0.09•sin(0.33 π• x - 96π•t )

- Physics -
**James**, Friday, July 13, 2012 at 12:01pmI see where my mistake was. I multiplied in the pi when I wasn't supposed to. This question had an obvious answer.

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