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August 29, 2014

Homework Help: Physics

Posted by James on Friday, July 13, 2012 at 1:08am.

The tension in a 2.6-m-long, 1.1-cm-diameter steel cable (ρ = 7800 kg/m3) is 860 N. What is the fundamental frequency of vibration of the cable?

The answer is 6.55 Hz.

I know that I'm going to use the formula:
f=nsqrt(T/4L^2u)
However, I'm not sure how to get the u for this equation. Any help is appreciated.

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