Posted by **James** on Friday, July 13, 2012 at 1:08am.

The tension in a 2.6-m-long, 1.1-cm-diameter steel cable (ρ = 7800 kg/m3) is 860 N. What is the fundamental frequency of vibration of the cable?

The answer is 6.55 Hz.

I know that I'm going to use the formula:

f=nsqrt(T/4L^2u)

However, I'm not sure how to get the u for this equation. Any help is appreciated.

- Physics -
**Damon**, Friday, July 13, 2012 at 1:17am
You need to find the mass of the cable and divide it by the length to get the mass per unit length.

Volume of cable = pi r^2 L

Mass of cable = pi r^2 L * 2.6

so

mass/length = 7800 * pi * (.011)^2

- Physics -
**James**, Friday, July 13, 2012 at 10:26am
Thank you! I was able to figure out the correct answer. However, in this case shouldn't (.011^2) be (.011/2)^2?

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