Wednesday
July 29, 2015

Homework Help: Physics

Posted by James on Friday, July 13, 2012 at 1:08am.

The tension in a 2.6-m-long, 1.1-cm-diameter steel cable (ρ = 7800 kg/m3) is 860 N. What is the fundamental frequency of vibration of the cable?

The answer is 6.55 Hz.

I know that I'm going to use the formula:
f=nsqrt(T/4L^2u)
However, I'm not sure how to get the u for this equation. Any help is appreciated.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members