1) Aluminum Chloride- Red- PH: 4.0

2) Sodium Carbonate - Violet- PH: 9.5

Ammonium Acetate - Yellow - PH: 6.5

the question is: explanation with equation to show hydrolysis

Could you please help me thank you.

Al(H2O)6^3+ H2O ==> Al(H2O)5(OH)^2+ + H3O^+

CO3^2- + HOH ==> HCO3^- + OH^-

NH4Ac + HOH ==> NH4OH + HAc
(NOTE:) Actually NH4OH doesn't exist; it is NH3 + H2O but I thought it easier to explain what is going on. When I was in school NH4OH was a compound; it has been shown not to exist and the above equation would have been the acceptable answer 40 years or so ago.

if it doesnt exist should I write

NH3 + H2O ---> NH4OH + HA ?

thank you.

Certainly! Hydrolysis is a chemical reaction that involves the reaction of a compound with water to form new products. To show hydrolysis, we need to write the balanced chemical equations for the reaction.

1) Aluminum Chloride: The formula for aluminum chloride is AlCl3. When it reacts with water, it undergoes hydrolysis to form aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl).

Equation: AlCl3 + 3H2O -> Al(OH)3 + 3HCl

2) Sodium Carbonate: The formula for sodium carbonate is Na2CO3. When it reacts with water, it undergoes hydrolysis to form sodium hydroxide (NaOH) and carbonic acid (H2CO3). However, carbonic acid spontaneously breaks down into water and carbon dioxide (CO2).

Equation: Na2CO3 + H2O -> 2NaOH + H2CO3 -> 2NaOH + H2O + CO2

Ammonium Acetate: The formula for ammonium acetate is NH4C2H3O2. When it reacts with water, it undergoes hydrolysis to form ammonium hydroxide (NH4OH) and acetic acid (CH3COOH).

Equation: NH4C2H3O2 + H2O -> NH4OH + CH3COOH

These equations show the hydrolysis reactions of Aluminum Chloride, Sodium Carbonate, and Ammonium Acetate.