posted by Anonymous on .
given the concentration of 125.0mg/L of Fe(2+)in the stock solution and the volume used which is (1.00mL) how do i calculate the concentration of iron(II) ions in mg/L?
i pipet 1.00mL of the stock into a 250ml volumetric flask!
If you take 1.00 mL of the stock soln contg 125 mg/L and dilute it to 250 mL, the concn in the 250 mL flask is
125.0 mg/L x (1/250) = ? mg/L