Posted by **Christopher** on Thursday, July 12, 2012 at 8:30pm.

Show that A =

[3 2 4

2 0 2

4 2 3]

is distinguishable even though one eigenvector has algebraic multiplicity 2. Do this by brute force computation. Why would you expect this to be true, even without calculation?

Then, for the A, write A= Q lambda Q^(T) where Q's columns are orthogonal (unit) vectors of A.

## Answer This Question

## Related Questions

- calculus - Using a graphing utility, graph and approximate the zeros and their ...
- Algebra - Find all of the zeros of the polynomial function and state the ...
- Algebra - Please help. Having a hard time with this. Find all of the zeros of ...
- precalc - Given a square matrix M, we say that a nonzero vector v is an ...
- Algebra - Find all of the zeros of the polynomial function and state the ...
- calculus - I really don't know where to start or go with this question...There ...
- Algebra - Find all of the zeros of the polynomial function and state the ...
- statistics - 2. A researcher measures the heart rate in a population of runners ...
- Math - I understand how to do these kind of problems except this one. Write the ...
- Physics - Two charged smoke particles exert a force of 4.2x10^-2 N on each other...

More Related Questions