Posted by BERNIE on Thursday, July 12, 2012 at 7:32pm.
Are these factorable
Beecause I tried and could figure it out
can you please help me thankyou
x^24x+32, x^2+14x+41,4x^8x712x^6+8x^5

algebra 117b  Steve, Thursday, July 12, 2012 at 11:55pm
x^24x32 = (x8)(x+4)
Since 41 is prime, x^2+14x+41 is not factorable. However, if there's a typo, and you meant x^2+14x+49, then that's (x+7)^2
4x^8x712x^6+8x^5 = 4x^5(x^2  3x + 2) = 4x^5(x1)(x2)
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