Posted by Jessica on Thursday, July 12, 2012 at 1:33pm.
m1=75 kg, m2 =50 kg. L=h=3m
Law of conservation of energy
PE1=KE1
m1•g•h = m1•v1²/2,
v1=sqrt(2•g•h) =sqrt(2•9.8•3)=7.67 m/s.
Law of conservation of momentum
m1•v1 =(m1+m2) •u
u= m1•v1/(m1+m2) =75•7.67/125 =4.6 m/s.
Law of conservation of energy
KE2=PE2
(m1+m2)•u²/2=(m1+m2)•g•H,
H= u²/2g=4.6²/2•9.8=1.08 m.
Related Questions
Language Arts - Boom, Boom- the music goes Boom, Boom- Feel the beat from head ...
Physics - A person swings a 0.33 kg tether ball tied to a 5.4 m rope in an ...
Cranes - 08/09/2005 Physics A crane is lifting a 200 pound object. The crane ...
physics - A person swings a 0.33 kg tether ball tied to a 5.4 m rope in an ...
physics - A stunt man whose mass is 70 kg swings from the end of a 4.4 m long ...
Resolution of vectors - A 1000kg load is suspended from the end of a horizontal ...
physics - A white-crowned sparrow flying horizontally with a speed of 1.65 m/s ...
Physics - On a hot summer day, a young girl swings on a rope above the local ...
Physics - An anvil hanging vertically from a long rope in a barn is pulled to ...
Physics - A bowling ball weighing 71.2 N is attached to the ceiling by a 3.80 m ...
For Further Reading